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Likurg_2 [28]
3 years ago
11

Solve 2/3 x d = 10/9

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

Exact Form:

d = 5 /3

Decimal Form:

d = 1.  6

Mixed Number Form:

d =1  2/ 3

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Based on the particular equation the answer should be 3
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2 years ago
Ricardo has 3 quarters, 1 done, 1 nickel, and 4 pennies. He gave 68 cents to his brother. How much money does Ricardo have left?
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The answer is 26 cents, Because to the process that is in the image.

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3 years ago
-0.5,1.25,-1/3,0.5,-5/3 ordered from least to greatest
vampirchik [111]

Answer:

Step-by-step explanation:

-5/3,-0.5,-1/3,0.5,1.25

8 0
3 years ago
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0
3 years ago
Read 2 more answers
If 2^5 x 5^2 = 2^n x 10^2, what is the value of n?
Marat540 [252]

Answer: x = 0

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

7 0
3 years ago
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