Given:
The equation is
![\dfrac{4560}{120}=38](https://tex.z-dn.net/?f=%5Cdfrac%7B4560%7D%7B120%7D%3D38)
To find:
The inverse operation for the equation using the knowledge of inverse operations.
Solution:
We have,
![\dfrac{4560}{120}=38](https://tex.z-dn.net/?f=%5Cdfrac%7B4560%7D%7B120%7D%3D38)
Here, 4560 is divided by 120. So, in this equation the operation is division.
We know that inverse operation of division is multiplication. So, multiply both sides by 120.
![\dfrac{4560}{120}\times 120=38\times 120](https://tex.z-dn.net/?f=%5Cdfrac%7B4560%7D%7B120%7D%5Ctimes%20120%3D38%5Ctimes%20120)
![4560=38\times 120](https://tex.z-dn.net/?f=4560%3D38%5Ctimes%20120)
It can be written as
![38\times 120=4560](https://tex.z-dn.net/?f=38%5Ctimes%20120%3D4560)
The inverse operation for the equation is
.
Therefore, the correct option is B.
Answer:
The answer is A.
Step-by-step explanation:
You can make a test by substituing x-coordinate into the equation :
![y = \frac{1}{2} x - 2](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20x%20-%202)
![let \: x = 0](https://tex.z-dn.net/?f=let%20%5C%3A%20x%20%3D%200)
![y = \frac{1}{2} (0) - 2](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%280%29%20-%202)
![y = - 2 \: (correct)](https://tex.z-dn.net/?f=y%20%3D%20%20-%202%20%5C%3A%20%28correct%29)
![let \: x = 2](https://tex.z-dn.net/?f=let%20%5C%3A%20x%20%3D%202)
![y = \frac{1}{2} (2) - 2](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%282%29%20-%202)
![y = 1 - 2](https://tex.z-dn.net/?f=y%20%3D%201%20-%202)
![y = - 1 \: (correct)](https://tex.z-dn.net/?f=y%20%3D%20%20-%201%20%5C%3A%20%28correct%29)
Answer:
y=6x-15
Step-by-step explanation:
y-y1=m(x-x1)
y-3=6(x-3)
y-3=6x-18
y=6x-18+3
y=6x-15
Answer:
The probability is 0.0005.
Explanation:
The stated question is incomplete. The complete question is as follows.
<em>A manufacturer is developing a new type of paint. Test panels were exposed to various corrosive conditions to measure the protective ability of the paint. Based on the results of the test, the manufacturer has concluded that the mean life before corrosive failure for the new paint is 155 hours with a standard deviation of 27 hours. If the manufacturer's conclusions are correct, find the probability that the paint on a sample of 65 test panels will have a mean life before corrosive failure of less than 144 hours. </em>
The mean life is 155 hours. Hence, μ = 155.
The standard deviation is 27 hours. Hence, σ = 27.
The sample size in 65 test panels. Hence, n = 65.
We can use the central limit theorem to find the probability that the mean life before corrosive failure is less than 144 hours. By the central limit theorem:
P(X < 144) = P[(X - μ) / (σ / √n) < (144 - 155) / (27/√65)]
P(X < 144) = P(Z < -3.2846)
Using the Z-value table for normal distribution, this value turns out to be:
P(X < 144) = 0.0005