What is the slope of the line on the graph ? (pls help omg)
1 answer:
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Answer:
∠ADB = γ/2 +90°
Step-by-step explanation:
Here's one way to show the measure of ∠ADB.
∠ADB = 180° - (α + β) . . . . . sum of angles in ΔABD
∠ADB + (2α +β) + γ + (2β +α) = 360° . . . . . sum of angles in DXCY
Substituting for (α + β) in the second equation, we get ...
∠ADB + 3(180° - ∠ADB) + γ = 360°
180° + γ = 2(∠ADB) . . . . . . add 2(∠ADB)-360°
∠ADB = γ/2 + 90° . . . . . . . divide by 2
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To find angles CXD and CYD, we observe that these are exterior angles to triangles AXB and AYB, respectively. As such, those angles are equal to the sum of the remote interior angles, taking into account that AY and BX are angle bisectors.
