Answer:
1 4/35
Step-by-step explanation:
All I did was do 5/7 + 2/5.
Answer:
The answer to the question: "Will Hank have the pool drained in time?" is:
- <u>Yes, Hank will have the pool drained in time</u>.
Step-by-step explanation:
To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:
- Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
- Available time = 360 minutes
Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:
- Volume of the pool = Deep * Long * Wide
- Volume of the pool = 2 m * 10 m * 8 m
- Volume of the pool = 160 m^3
Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:
Now, we use a rule of three:
If:
- 1 m^3 ⇒ 264.172 gal
- 160 m^3 ⇒ x
And we calculate:
(We cancel the unit "m^3)- x = 42267.52 gal
At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:
- Time to drain the pool =
(We cancel the unit "gallon") - Time to drain the pool = 325.1347692 minutes
- <u>Time to drain the pool ≅ 326 minutes</u> (I approximate to the next number because I want to assure the pool is drained in that time)
As we know, <u><em>Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes</em></u>.
Answer:
-25
Step-by-step explanation:
g(f(3))= g(-5)
=4(-5)-5
= -20-5
=-25
a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.
b. The area of the outfield is about 39,584 sq. ft..
<h3>What is the Perimeter of a Quarter Circle?</h3>
Perimeter of circle = 2πr
Perimeter of a quarter circle = 2r + 1/4(2πr).
a. The length of the fence around the field = perimeter of the quarter circle fence
= 2r + 1/4(2πr).
r = 250 ft
Plug in the value
The length of the fence around the field = 2(250) + 1/4(2 × π × 250)
= 892.7 ft.
b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)
= 1/4(πR²) - πr²
R = radius of the full field = 250 ft
r = radius of the infield = 110/2 = 55 ft
Plug in the values
Size of the outfield = 1/4(π × 250²) - π × 55²
= 49,087 - 9,503
= 39,584 sq. ft.
Learn more about perimeter of quarter circle on:
brainly.com/question/15976233
Answer:
60.32
Step-by-step explanation: