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3 years ago

Whatis the answer to the problem

Mathematics

1 answer:

Stels [109]3 years ago

8 0

Answer:

slope = $-\frac{1}{8}$

Step-by-step explanation:

Use the slope formula given in the question to solve for the slope. The $m$ is the variable representing the slope. The $x_1$ and $y_1$ values are x and y values of one point. The $x_2$ and $y_2$ are x and y values of another point.

So, use the x and y values of the points given and substitute them in the correct order into the formula:

$m = \frac{(7)-(9)}{(10)-(-6)}\\m = \frac{7-9}{10+6} \\m = \frac{-2}{16} \\m = -\frac{1}{8}$

Thus, the slope is $-\frac{1}{8}$ .

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The perimeter of a rectangle is 36m. If its length is increased by 1m and the width is increased by 2m, its area will increase b

maw [93]

Answer:

80 m^2

Step-by-step explanation:

The given information lets you write two equations involving length (x) and width (y).

2(x +y) = 36 . . . . the perimeter is 36 m
(x+1)(y+2) -xy = 30 . . . . increasing the length and width increases area

The second of these equations simplifies to another linear equation, giving a system of linear equations easily solved.

xy +y +2x + 2 -xy = 30

2x +y = 28 . . . . . . . subtract 2

Dividing the first equation by 2 gives

x +y = 18

and subtracting this from the above equation gives ...

(2x +y) -(x +y) = 28 -18

x = 10

Then

y = 18 -10 = 8

The area of the original rectangle is xy = 10·8 = 80 m^2.

4 0

3 years ago

Can you guys please help!

yuradex [85]

Answer:

5 for the first and 4x for the second one also plz give heart

Step-by-step explanation:

i just know

4 0

3 years ago

How do you find the f(x) inverse using fractions?

fenix001 [56]

For example.. 1) switch places of x and y. x=3y+1 x=3 y +1
2) try to solve for y. so multiply the denominator by x to get rid of it
3) after multiplying, ur left with xy+x=3 x y + x=3
4) that converts to 2xy= x y =3
5) get rid of 2x on left by placing it on the right
6) convert y to inverse function

4 0

3 years ago

Four points are always coplanar if check all that apply

Elza [17]

Hey there,

Your question states: Four points are always coplanar if . . .

Your correct answer from the questions above would be they lie in the same place

The definition of the word $\boxed{coplanar}$ means : In the same place.

So . .Four points are always coplanar if they lie in the same place.

Hope this helps many.

~Jurgen

5 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

2 years ago