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Effectus [21]
4 years ago
9

At top speed jaguar can run 2.5 miles in 3 mins what is it’s speed in mph

Mathematics
1 answer:
Alekssandra [29.7K]4 years ago
8 0

Answer:

50 mph

Step-by-step explanation:

<u>Speed of Jaguar given:</u>

  • 2.5 miles in 3 mins
  • Speed in mph = ?

<u>Solution:</u>

  • 2.5 miles / 3 mins =
  • 2.5 miles / (3/60 h) =
  • 2.5*60/3 mph =
  • 2.5*20 mph =
  • 50 mph
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X – 2y = 15<br> 2x + 3y = 2
lesya [120]

Answer:

you combine like terms and that will get you your answer

Step-by-step explanation:

2x+x

2y+3y

15+2

to get your answer

3 0
4 years ago
Manuela solved the equation 3−2|0.5x+1.5|=2 for one solution. Her work is shown below. 3−2|0.5x+1.5|=2 −2|0.5x+1.5|=−1 |0.5x+1.5
adoni [48]

Answer:

x = - 4

Step-by-step explanation:

Given

3 - 2 |0.5x + 1.5 | = 2 ( subtract 3 from both sides )

- 2 |0.5x + 1.5 | = - 1 ( divide both sides by - 2 )

|0.5x + 1.5 | = 0.5

The absolute value function always gives a positive value, however, the expression inside can be positive or negative, thus

0.5x + 1.5 = 0.5 ( subtract 1.5 from both sides )

0.5x = - 1 ( divide both sides by 0.5 )

x = - 2 ← solution Manuela obtained

OR

-(0.5x + 1.5) = 0.5 ← distribute parenthesis on left side by - 1

- 0.5x - 1.5 = 0.5 ( add 1.5 to both sides )

- 0.5x = 2 ( divide both sides by - 0.5 )

x = - 4 ← other solution to the equation

5 0
3 years ago
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What is the greatest common factor of 5 and 35?
rjkz [21]
5 is the highest common factor
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3 years ago
What is -6k + 7k? Pleasee answer
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8 0
3 years ago
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Solve the question in the picture and write the correct answer​
zlopas [31]

Answer:

  36.24 cm²

Step-by-step explanation:

The shaded region is the inscribed circle in the isosceles triangle. In order to find its area, we need to know the radius of the circle.

__

One way to find the radius of the circle is to make use of the Angle Bisector theorem. It tells us an angle bisector divides the sides of a triangle proportionately. In the attached figure, that means angle bisector CD divides segment AE in proportion to sides CA and CE.

<h3>Side Length</h3>

To make use of this theorem, we need to know the length of side CA. That is the hypotenuse of right triangle AEC, so can be found using the Pythagorean theorem. Isosceles triangle ABC is given as having height AE=10 and base BC = 12.

  CA² = CE² +AE²

  CA² = 6² +10² = 136 . . . . . . . CE is half the base length: 12/2 = 6

  CA = √136 = 2√34

__

<h3>Radius</h3>

Now we can write the proportion using the angle bisector theorem.

  DE/CE = DA/CA

  r/6 = (10 -r)/(2√34)

  r√34 = 3(10 -r) . . . . . . . multiply by 6√34

  r(3 +√34) = 30

  r = 30/(3 +√34)

__

<h3>Area</h3>

From this, we can find the area of the shaded circle to be ...

  A = πr² = (3.14)(30/(3 +√34))²

  = 3.14·900/(43 +6√34) ≈ 36.2374 . . . cm²

The area of the shaded region is about 36.24 cm².

_____

<em>Additional comment</em>

Using area considerations, the formula for the radius of the inscribed circle in an isosceles triangle with base 'b' and sides 'a' can be found to be ...

  r=\dfrac{b}{2}\sqrt{\dfrac{2a-b}{2a+b}}

For a=√136 and b=12, this becomes ...

  r=\dfrac{12}{2}\sqrt{\dfrac{2\sqrt{136}-12}{2\sqrt{136}+12}}=6\sqrt{\dfrac{(\sqrt{34}-3)^2}{34-9}}=1.2(\sqrt{34}-3)\approx3.39714

This is the same value we found above.

3 0
2 years ago
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