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Arisa [49]
3 years ago
7

How would you describe the tick marks on the number line between the tenths?

Mathematics
1 answer:
allsm [11]3 years ago
8 0

Answer:

millimeters....

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Who is faster The Flash or Quicksilver?<br><br><br><br> I want a source to back up your answer
nikdorinn [45]

Answer:

The flash.

Step-by-step explanation:

He used to max out at Mach 1. Since crossover events are exceedingly rare, it is safe to assume that if you were comparing their speeds, the Flash is <u><em>consistently</em></u> faster than Quicksilver, though operationally speaking both could be consider comparable since their feats tend to be done at the same overall speed.

3 0
4 years ago
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Brandon’s family went out to dinner. The dinner bill was $85 and the family gave the server a 20% tip. How much is the tip?
gregori [183]

Answer: The tip is $17

Step-by-step explanation: You multiply $85 by .2 to get this answer.

7 0
3 years ago
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Y=x^2+5x-8 to factored form
almond37 [142]

Answer:

Factor and set each factor equal to zero. Y=x2+5x−8

Step-by-step explanation:

5 0
2 years ago
When Nabhitha goes bowling, her scores are normally distributed with a mean of 115
frutty [35]

Answer:

By the Empirical Rule, in 99.7% of the games that Aubree bowls she scores between 148 and 232Step-by-step explanation:The Empirical Rule states that, for a normally distributed random variable:68% of the measures are within 1 standard deviation of the mean.95% of the measures are within 2 standard deviation of the mean.99.7% of the measures are within 3 standard deviations of the mean.In this problem, we have that:Mean = 190Standard deviation = 14Using the empirical rule, what percentage of the games that Aubree bowls does she score between 148 and 232?148 = 190 - 3*14So 148 is 3 standard deviations below the mean.232 = 190 + 3*14So 232 is 3 standard deviations above the meanBy the Empirical Rule, in 99.7% of the games that Aubree bowls she scores between 148 and 232

7 0
2 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
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