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3 years ago

Juanita has 16 model cars and 48 model trains. What is the ratio of the wmber of trains to the member of cars?

Mathematics

1 answer:

svetoff [14.1K]3 years ago

6 0

Answer:

1:3

Step-by-step explanation:

but thats not and answer

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Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, −1), and S (1, −2). Russell and Jamie have both classified PQRS diffe

Rudiy27

Answer:

the answer is russell

3 0

2 years ago

Let F(x, y, z) = (5ex sin(y))i + (5ex cos(y))j + 7z2k. Evaluate the integral C F · ds, where c(t) = 8 t , t3, exp( t ) , 0 ≤ t ≤

maria [59]

I'm going to assume this reads

$\vec F(x,y,z)=5e^x\sin y\,\vec\imath+5e^x\cos y\,\vec\jmath+7z^2\,\vec k$

and the path $C$ is parameterized by

$\vec c(t)=8t\,\vec\imath+t^3\,\vec\jmath+e^t\,\vec k$

with $0\le t\le1$ . Under this parameterization,

$\vec F(x,y,z)=\vec F(x(t),y(t),z(t))=5e^{8t}\sin(t^3)\,\vec\imath+5e^{8t}\cos(t^3)\,\vec\jmath+7e^{2t}\,\vec k$

and

$\mathrm d\vec c=\dfrac{\mathrm d\vec c}{\mathrm dt}\,\mathrm dt=(8\,\vec\imath+3t^2\,\vec\jmath+e^t\,\vec k)\,\mathrm dt$

Then in the integral,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec s=\int_0^1\vec F(x(t),y(t),z(t))\cdot\frac{\mathrm d\vec c}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(7e^{3t}+15e^{8t}t^2\cos(t^3)+40e^{8t}\sin(t^3))\,\mathrm dt\approx\boxed{12586.5}$

(It's unlikely that an exact answer can be found in terms of elementary functions)

4 0

3 years ago

How many bars of soap and toothbrushes are in each package? HHEEELLLPP!!!

Darya [45]

Hey you, i don’t think anyone can answer that with that little info...

5 0

3 years ago

(7w3-4w+3)+(5w3-3w-3)

ki77a [65]

That is a simple polynomial addition:
(7w3-4w+3)+(5w3-3w-3)
= (7w^3 - 4w + 3) + (5w^3 - 3w - 3)
= 7w^3 - 4w + 3 + 5w^3 - 3w - 3
= 12w^3 - 7w
= w(12w^2 - 7)

7 0

3 years ago

Help with 1 and 3 if possible show work

Vinvika [58]

1)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+r\right)^{t}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$600\\
r=rate\to 1.6\%\to \frac{1.6}{100}\to &0.016\\
t=years\to &2
\end{cases}
\\\\\\
A=600\left(1+0.016\right)^{2}$

3)

$\bf V(t)=1350(1.017)^t\implies 
\begin{array}{llllll}
V(t)&=&1350(&1 +& 0.017&)^t\\
A&=&P(&1+&\boxed{r}&)^t
\end{array}$

notice the rate "r"... now, is in decimal format, as you saw on 1) is just r/100 so 1.6% was really 1.6/100 or 0.016 anyhow

to get the percentage form, just multiply it by 100

5 0

4 years ago