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Elena-2011 [213]
3 years ago
12

Solve the system of equations x - y = 12 and x + 7y = -20 by combining the equations.

Mathematics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:

x= 8, y= -4

Step-by-step explanation:

You can subtract one equation by another to eliminate x

(x-y)-(x+7y)=12-(-20)

-8y = 32

y= -4

Substitute y =  -4 in the first equation:

x-(-4) = 12

x =8

iogann1982 [59]3 years ago
7 0

Answer:

x=16, y=-4

Step-by-step explanation:

-1(x-y=12)

x+7y=-20

-x+y=-12

x+7y=-20

8y=-32

y=-4

x-4=12

x=16

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drek231 [11]

Answer:

the first one, 5(x-4) + 29

Step-by-step explanation:

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3 years ago
Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher
Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find <em>t</em>.

A(t)=A_{0}(1/2)^t^/^h

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For A_{0 let's just assume that there are 100 original  atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. <em>h</em> is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

74=100(1/2)^t^/^5^7^3^0

Now, solve. First, divide by 100.

0.74=(0.5)^t^/^5^7^3^0

Take the log of everything

log(0.74)=\frac{t}{5730} log(0.5)

Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the <em>t</em> and get

5730\frac{log(0.74)}{log(0.5)} =t

Use your calculator to solve that giant mess for <em>t </em>and you'll get that <em>t</em> is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0
3 years ago
What are compatible numbers?
posledela
Numbers that are close in value to the actual numbers.
4 0
3 years ago
Read 2 more answers
A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s
Umnica [9.8K]

Answer:

88.51 is the minimum score needed to receive a grade of A.          

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73

Standard Deviation, σ = 11

We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.0793.

P( X \geq x) = P( z \geq \displaystyle\frac{x - 73}{11})=0.0793  

= 1 -P( z \leq \displaystyle\frac{x - 73}{11})=0.0793  

=P( z \leq \displaystyle\frac{x - 73}{11})=0.9207  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.410) = 0.9207

\displaystyle\frac{x - 73}{11} = 1.410\\x =88.51  

Hence, 88.51 is the minimum score needed to receive a grade of A.

3 0
3 years ago
If 16 counters is 4/9 what is the ONE?
klemol [59]
(4/9)/16 = 4/(9*16) = 4/(4*4*9) = 1/(4*9) = 1/36

One counter is \frac{1}{36}<span> if 16 of them are </span>\frac{4}{9}
5 0
3 years ago
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