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STALIN [3.7K]
3 years ago
10

What is the mid point of the x-intercepts of f(x)=(x-2)(x-4)?

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Oxana [17]3 years ago
3 0

Answer:

The x-int.s are (2, 0) and (4, 0) so the midpoint will be (3, 0).

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Solve for x. Leave your answer in simplest radical form.
strojnjashka [21]

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

\boxed{ \large \boxed{h {}^{2}  =  {b}^{2} + p{}^{2}  }}

note :

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let's solve for " y² " first ( square of other missing side )

➢ \:  \:  {y}^{2}  =  {8}^{2}  + 3 {}^{2}

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now let's solve for " x " , by using pythagorous theorem

➢ \:  \:  {x}^{2}  =  {y}^{2}  +  {6}^{2}

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Approximate :

➢ \:  \: 10.44 \:  \: units

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3 years ago
How would the expression x^2+27 be rewritten using sum of cubes?
nydimaria [60]
Assuming the square is not a typo, one can write


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=(x^{2/3}+3)\bigg(x^{4/3}-3x^{2/3}+9\bigg)
6 0
3 years ago
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