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3 years ago

How can you find a function that has these roots?

Mathematics

1 answer:

EleoNora [17]3 years ago

7 0

Answer:

The quadratic function x^2 - 5x + 6 =0

can be factored into (x -3) * (x-2)

And it would have roots of 3 and 2

So, if a cubic functions has roots of 2, 3 and 5 then its factors are

(x -2)* (x -3) * (x -5)

Multiply it out to get the equation.

Dunno if that was what you were looking for but i did what i can....

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Eighteen pepperoni for each pizza

andrew-mc [135]

What do you mean? whats the question?

6 0

4 years ago

Annie has 3/2 pounds of cookie dough. If she needs 1/16 of a pound of cookie dough to make one cookie, how many cookies can she

Zanzabum

Answer:

$\boxed{\sf 24\ cookies}$

Step-by-step explanation:

1 cookie = 1/16 of a pound of cookie

If we want to find how many cookies can be made by 3/2 pounds ( 1.5 pounds) then we need to divide 3/2 pounds by 1/16

=> $\frac{3}{2} / \frac{1}{16}$

=> $\frac{3}{2} * 16$

=> 3*8

=> 24 cookies

4 0

3 years ago

Read 2 more answers

The perimeter of a rectangle is 343434 units. Its width is 6.56.56, point, 5 units. Write an equation to determine the length (l

stiv31 [10]

Answer:

Step-by-step explanation:

perimiter=2(Length+Width)

P=2(L+W)

solve for L

distribute

P=2L+2W

minus 2W

P-2W=2L

divide by 2

\frac{P-2W}{2}=L

given that P=34 units and W=6.5 units

\frac{34-2(6.5)}{2}=L

the equation would be L=p2w/2 or L= p/2=w

5 0

3 years ago

Margo has $80 to spend. She wants to buy

ivolga24 [154]

Answer:

The greates amount she could buy is 4

8 0

3 years ago

A random sample of 384 people in a mid-sized city (city one) revealed 112 individuals who worked at more than one job. A second

Svetlanka [38]

Answer:

99% confidence interval is:

(0.00278 < P1 - P2< 0.15921)

Step-by-step explanation:

For calculating a confidence intervale for the difference between the proportions of workers in the two cities, we calculate the following:

$[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }$

Where $p_{1}$ : proportion sample of individuals who worked

at more than one job in the city one

$n_{1}$ : Number of respondents in the city one

$p_{1}$ : proportion sample of individuals who worked

at more than one job in the city two

$n_{1}$ : Number of respondents in the city two

Then

α = 0.01 and α/2 = 0.005

and $z_{\alpha/2} = 2.575$

$p_{1} = \frac{112}{384} = 0.2916$

$p_{2} = \frac{91}{432} = 0.2106$

$n_{1}= 384$ and $n_{2}= 432$

The confidence interval is:

$[(0.2916 - 0.2106) \pm 2.575 \sqrt{\frac{0.2916(1-0.2916)}{384} + \frac{0.2106(1-0.2106)}{432} }$

(0.00278 < P1 - P2< 0.15921)

5 0

3 years ago