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Marta_Voda [28]
4 years ago
9

2^X = 17^X How do you solve that equation?

Mathematics
1 answer:
Kobotan [32]4 years ago
5 0

For this case we must solve the following equation:

2 ^ x = 17 ^ x

For this, we follow the steps below:

We find the Neperian logarithm on both sides of the equation to remove the variable from the exponent

ln (2 ^ x) = ln (17 ^ x)

We use one of the logarithm properties to extract x from the exponent:

xln (2) = xln (7)

We subtract xln (7) on both sides of the equation:

xln (2) -xln (7) = 0

We take x common factor:

x (ln (2) -ln (7)) = 0

We divide between(ln (2) -ln (7))on both sides of the equation, then:

x = 0

Answer:

x = 0

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