Question

2^X = 17^X How do you solve that equation?

Answer 1

For this case we must solve the following equation:

$2 ^ x = 17 ^ x$

For this, we follow the steps below:

We find the Neperian logarithm on both sides of the equation to remove the variable from the exponent

$ln (2 ^ x) = ln (17 ^ x)$

We use one of the logarithm properties to extract x from the exponent:

$xln (2) = xln (7)$

We subtract xln (7) on both sides of the equation:

$xln (2) -xln (7) = 0$

We take x common factor:

$x (ln (2) -ln (7)) = 0$

We divide between$(ln (2) -ln (7))$on both sides of the equation, then:

$x = 0$

Answer:

$x = 0$