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babunello [35]
3 years ago
10

Question above please help due in a few minutes

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

here x\geq3

the circle is filled so it includes the value

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Determine which ordered pair is a solution of y = –5x + 10. a. (–15, 5)
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Y = - 5 x + 10
A ) x = - 15, y = 5
5 = 75 + 10
5 ≠ 85
B ) x = 2, y = 0
0 = - 5 · 2 + 10
0 = 0  ( correct )
C ) x = - 1,  y = - 5,
- 5 = 5 + 10
- 5 ≠ 15
D ) x = 3, y = 25
25 = - 15 + 10
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Answer:
B ) ( 2, 0 )
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​write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)
Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

log_{4 }6ab

This can be written as

log_{4 }6 \times a \times b

From one of the rules of logarithm, we have that

log_{x }yz= log_{x }y + log_{x }z

Thus,

log_{4 }6 \times a \times b  becomes

log_{4 }6 + log_{4 }a + log_{4 }b

This can be further simplified into

log_{4 }3 \times 2 + log_{4 }a + log_{4 }b

log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b

If desired, this can be further simplified into

log_{4 }3 + log_{2^{2}  }2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b

\frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0
2 years ago
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