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Thepotemich [5.8K]
3 years ago
6

Help me soon please !! Math question

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

Step-by-step explanation:

area = L x W so the answer would be 72.

You add 8 and 4 to get 12 them multiply by 6.

elena-14-01-66 [18.8K]3 years ago
6 0

Answer:

8 x 6 = 48 plus 4 x 6 = 24 divided by 2 = 12 so 48 + 12 = 6 0

Step-by-step explanation:

Divide the figure into a rectangle and a triangle find the area of the two then add it up like I said in my answer.

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What is the quotient and remainder of (4x^3-3x^2+x+7)/(x-2)
viva [34]

Answer:

4x^2+11x+23 r53

Step-by-step explanation:

4x^3-3x^2+x+7 / x-2

2 | 4 -3  1   7

        8 22 46

___________

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This means 4x^2+11x+23 with a remainder of 53

7 0
3 years ago
Find the equation of the line that is parallel to the given line and passes through the given point
Sati [7]

Answer:

\huge\boxed{y=-\dfrac{1}{4}x-1\to x+4y=-4}

Step-by-step explanation:

\text{Let}\ k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\==========================\\\\\text{We have}\ x+4y=-6.\\\text{Convert to the slope-intercept form:}\\\\x+4y=-6\qquad\text{subtract}\ x\ \text{from both sides}\\\\4y=-x-6\qquad\text{divide both sides by 4}\\\\y=\dfrac{-x}{4}-\dfrac{6}{4}\\\\y=-\dfrac{1}{4}x-\dfrac{3}{2}\to m_1=-\dfrac{1}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (9,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}\\\\x=9,\ y=-3\\\\-3=-\dfrac{1}{4}(9)+b\\\\-3=-\dfrac{9}{4}+b\qquad\text{add}\ \dfrac{9}{4}\ \text{to both sides}\\\\-\dfrac{12}{4}+\dfrac{9}{4}=b\to b=-\dfrac{3}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (8,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}

x=8,\ y=-3\\\\-3=-\dfrac{1}{4}(8)+b\\\\-3=-2+b\qquad\text{add 2 to both sides}\\\\-1=b\to b=-1

\text{Therefore the equation is:}\ y=-\dfrac{1}{4}x-1.\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4y=-x-4\qquad\text{add}\ x\ \text{to both sides}\\\\x+4y=-4

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Answer:

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