If you can find one leg of a triangle to be congruent to a leg on the other triangle, then you can use the HL (hypotenuse leg) theorem. If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.
Answer:
`18. x=9
19. x=4
20. x=25,5
21. x=3
22. x=3,5
23. x=10
Step-by-step explanation:
I'm guessing this is a parallelogram or something, so VR=TS and RS=VT
therefore, y=x+11 and x+2=y-3x
y=x+11 , 2=y-4x
y=x+11 , y=4x+2
then use the process of elimination:
y=4x+2 then plug in: y=3+11
- y=x+11 y=14
0=3x-9 I think this is how you'd do it, tbh it's just an educated
3x=9 , x=3 guess. Btw, sorry if it looks weird
Answer:
f(-5)=240
g(-7)=-33
Step-by-step explanation:
1) f(x)=3x^2 - 3x
f(-5)= 3×(-5)^2 - 3×(-5) = -15^2 + 15= 225 + 15=240
2) g(x)=5x + 2
g(-7)= 5×(-7) + 2= -35+2=-33
Answer: 20%
Step-by-step explanation:
1 5
100 x
100*5/1 = 20%
