Y = -(x – 4)^2+3 Standard form

Mathematics

1 answer:

Alchen [17]2 years ago

7 0

Answer:

$y=-x^2+8x-13$

Step-by-step explanation:

The standard form of a quadratic equation is:

$y=ax^2+bx+c$

so to rewrite the equation in this form we do the following steps:

$y=-(x-4)^2+3$

First we apply the formula $( a-b)^2 = a^2 -2ab + b^2\\$

so now the equation becomes,

$y=-(x-4)^2+3\\y=-((x)^2-2(x)(4)+(4)^2)+3\\y=-(x^2-8x+16)+3\\y=-x^2+8x-16+3\\y=-x^2+8x-13\\y=ax^2+bx+c\\$

now if we compare the equation that we got with our standard form it is in the exact format thus the value of a = -1 , b = 8 and c = -13

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ExtremeBDS [4]

Answer:

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Step-by-step explanation:

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