All categories

2 years ago

Plz plz help help help plz plz help plz

Mathematics

2 answers:

Crank2 years ago

8 0

Answer:25.50 an hour

Step-by-step explanation:

uranmaximum [27]2 years ago

4 0

Answer:

since your adding to hours each time youll have 11, then the answer would be d the last one :)

Step-by-step explanation:

You might be interested in

How do I construct a sample data set for which n=7, x=9(x bar), and s=0?

JulijaS [17]

When the standard deviation = 0, there is no deviation at all. So the numbers are all the same. And there are seven of them. And the average is nine.
So the sample data set would just be seven 9s.

4 0

3 years ago

Veronica Foaley sells evening jackets sewn with metallic threads and beads. She wants to set a price of $600 for a jacket. The m

boyakko [2]

The most she can pay for the jacket is $375 (=600/(100%+60%)) assuming this is the cost of the jacket before it sewn with metallic threads and beads. A markup is a difference between the production cost and the selling price in order to cover the additional cost related to the product. Based on the data, she wants to keep the 60% for covering the cost.

6 0

3 years ago

Read 2 more answers

A ferritin test is a popular test to measure a person’s current iron stores. in women, ferritin is normally distributed with a m

MArishka [77]

Given:
μ = 89 ng/ml, population mean
σ = 23 ng/ml, population standard deviation

Random variable, x = 100
To test P(x < 100), calculate the z-score.
z = (x-μ)/σ = (100 - 89)/23 = 0.4783

From standard tables, obtain
P(x < 100) = 0.6838 = 68.4%

Answer: 68.4%

7 0

3 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve