A standard deck of 52 cards has 4 suits (spades, clubs, hearts, and diamonds) with 13 different cards (ace, 2, 3, 4, 5, 6, 7, 8,
Inessa [10]
Answer:
P(a pair with matching cards in different suits) = 1/52
Step-by-step explanation:
We are told that there are 4 suites and each suit has 13 different cards. This is a total of 52 cards.
Thus;
Probability of selecting one card of a particular suit = 13/52 = 1/4
If we now want to select a matching card of another suit without replacing the first one, then, we now have; 52 - 13 = 39 cards. Now, there are only 3 matching cards of the 3 remaining suits that is same as the first card drawn.
Thus; probability = 3/39 = 1/13
Thus;
P(a pair with matching cards in different suits) = 1/4 × 1/13
P(a pair with matching cards in different suits) = 1/52
Answer:
i think it is b
Step-by-step explanation:
Quotient: 5x+5
Remainder: -5
