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Zepler [3.9K]
3 years ago
13

Someone please help me

Mathematics
2 answers:
nadya68 [22]3 years ago
6 0
The formula is \pi rs+  \pi r^{2}, where s is slant height.

so,
= 3.14X4X7+3.14X4^{2}
= 87.92+50.24
= 138.16cm^{2}
babymother [125]3 years ago
5 0
There is a rounding error... So 138.16 cm^2 is the answer

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Which is a correct first step in solving 5 – 2x < 8x – 3?
Elenna [48]

Answer:

5 < 10x - 3

Step-by-step explanation:

5 - 2x < 8x - 3

Add '2x' to both the sides

5 - 2x + 2x < 8x + 2x - 3

5 < 10x - 3

3 0
3 years ago
URGENT: statistics: A researcher wishes to estimate the percentage of adults who support abolishing the penny what size sample s
irina1246 [14]

Using the margin of error for the z-distribution, the sample sizes are given as follows:

a) 822.

b) 1068.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

We have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Item a:

The estimate is of \pi = 0.26, hence we solve for n when M = 0.03.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.26(0.74)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.26(0.74)}

\sqrt{n} = \frac{1.96\sqrt{0.26(0.74)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.26(0.74)}}{0.03}\right)^2

n = 821.2

A sample of 822 is needed.

Item b:

No prior estimate, hence \pi = 0.5.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 1067.11

A sample of 1068 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
The length of a photograph of Mr. Lemley playing golf is 1475 inches. If the area
Mice21 [21]

Answer:

1.12 × 10^-3

Step-by-step explanation:

The computation of the width of the photograph is as follows:

As we know that

Area of the rectangle = length × width

33 ÷ 20 square inches = 1475 inches × width

So, the width is

= Length ÷ area

=  1475 inches ÷ (33 ÷ 20 square inches)

= 1.12 × 10^-3

8 0
3 years ago
Solve: (-5/6) × (9/20) + (-5/6) × 7/25 = ?​
jonny [76]

\bf \underline{★ How \:to\: do -} \\

Here, we are given with four fractions to multiply two of them and to add two of them. If we add them directly by taking the LCM and adding them is not a similar way. We can clearly observe that in those four fractions, we have two fractions as common i.e, we have two fractions as same. If we have two fractions or numbers as same, we can solve the sum by an other concept called as distributive property. In this property, we multiply the common fraction with the sum of other two fractions. This concept can also be done with fractions as well as integers. So, let's solve!!

\:

\bf \underline{➤ Solution-} \\

{\tt \leadsto \dfrac{(-5)}{6} \times \dfrac{9}{20} + \dfrac{(-5)}{6} + \dfrac{7}{25}}

Group the non-common fractions in bracket.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9}{20} + \dfrac{7}{25} \bigg)}

First we should solve the numbers in bracket.

LCM of 20 and 25 is 100.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9 \times 5}{20 \times 5} + \dfrac{7 \times 4}{25 \times 4} \bigg)}

Multiply the numerators and denominators in the bracket.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45}{100} + \dfrac{28}{100} \bigg)}

Now, write both numerators in bracket with a common denominator.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45 + 28}{100} \bigg)}

Now, add the numerators in bracket.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{73}{100} \bigg)}

Write the numerator and denominator in lowest form by cancellation method.

{\tt \leadsto \dfrac{\cancel{(-5)} \times 73}{6 \times \cancel{100}} = \dfrac{(-1) \times 73}{6 \times 20}}

Now, multiply the numerators and denominators.

{\tt \leadsto \dfrac{(-73)}{120}}

\:

{\red{\underline{\boxed{\bf So, \: the \: answer \: obtained \: is \: \: \dfrac{(-73)}{120}}}}}

3 0
3 years ago
If point C is between points A and B, then ___ + CB = AB. A. ABC B. AB C. CA D. BC
lozanna [386]

Here we are given that C is between A and B.

So using the midpoint rule, sum of whole length AB will be addition of lengths AC and BC

so we can say that option C. CA is the correct choice as it satisfies the given condition.

3 0
3 years ago
Read 2 more answers
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