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Marrrta [24]
3 years ago
6

Solve for x. 2x+3y=20 -2x+y=4

Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

x = 1

Step-by-step explanation:

-2x + y = 4

y = 2x + 4

2x + 3y = 20

2x + 3(2x + 4) = 20

2x + 6x + 12 = 20

8x + 12 = 20

8x = 8

x = 1

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A right triangle has a leg with a length of 18 and a hypotenuse with a length of 31 yards. Find the length of the other leg (nea
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25.2

Step-by-step explanation:

A squared + b squared = c squared

6 0
3 years ago
A recipe calls for 1/4 cup of brown sugar for every 2/3 cup of white sugar. How many cups of brown sugar is required for every c
sammy [17]

The right answer is Option B: 3/8

Step-by-step explanation:

Given,

1/4 cup of brown sugar is for 2/3 cup of white sugar.

Ratio of brown sugar to white sugar = \frac{1}{4}:\frac{2}{3}

Let,

x be the brown sugar required for 1 cup of white sugar.

Ratio of brown sugar to white sugar = x:1

Using proportion;

Ratio of brown sugar to white sugar :: Ratio of brown sugar to white sugar

\frac{1}{4}:\frac{2}{3}::x:1

Product of mean = Product of extreme

\frac{2}{3}*x=\frac{1}{4}*1\\\frac{2}{3}x=\frac{1}{4}

Multiplying both sides by 3/2

\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2}\\x=\frac{3}{8}

3/8 cups of brown sugar is required for 1 cup of white sugar.

The right answer is Option B: 3/8

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4163549
  • brainly.com/question/4168505

#LearnwithBrainly

3 0
3 years ago
What is the product 4 times 1000​
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The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
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