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3 years ago

Write the following in scientific notation: 1. 5,400,000,000.=

2 answers:

7 0

ANSWER: 5.4 x 10 to the 9th power

Whenever you have a large number, you must shift the decimal point to the left to get a number between 1-9.

Kazeer [188]3 years ago

4 0

Answer:

5.4x10^9

Step-by-step explanation:

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Find the x-intercept of the following equation. Simplify your answer.

lawyer [7]

Answer:

y intercept=3/2

Step-by-step explanation:

First of all, write it in slope intercept form

y=-1/6x+3/2

y=mx+b

b=y-intercept

y intercept=3/2

7 0

3 years ago

Read 2 more answers

Here's another Math one worth 10.

tia_tia [17]

In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
The short leg is the side opposite the 30 degree angle. If the short leg =x, then the hypotenuse = 2x

The ratio of the short leg to the hypotenuse in the given triangle is cos(60°)

$
cos(60^o) = \frac{adjacent \ side}{hypotenuse } = \frac{x}{2x} = \frac{1}{2}$

Answer is C. 1:2

7 0

2 years ago

30 points please answer honestly. Geometry help needed. D is 9.32

Vadim26 [7]

Answer:

7.75 m

Step-by-step explanation:

First find the circumference. Use the formula C = 2πr

C = 2(3.14)(3)

C = 18.84

148° is a fraction of the entire circle which is 360°

Multiply

18.84/1 x 148/360

2788.32/360

7.745

4 0

2 years ago

there are 6 men and 8 pets the there is half less more woman then the children. how many woman are there?

gogolik [260]

There are 7 women in the room.

8 0

2 years ago

Read 2 more answers

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: 3 tires are blemished.

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: 2 tires are blemished.

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: 1 tires are blemished.

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: No tires are blemished.

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

2 years ago