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MAXImum [283]
3 years ago
8

At the track meet, Justin won the 100 meter race in 12.61 seconds. Shawn won the 200-meter race in 26.38 seconds. Which runner r

an at a faster average rate?
Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
Justin 100/12.61 = 7.93 m/s
shawn 200/26.38 = 7.58 m/s
shawn is faster
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3 years ago
Find the 53rd term of the arithmetic sequence<br> 27,11, -5
vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

a_{n+1} = a_{n} + d

In which d is the common diference between each term, that is, d = a_{3} - a_{2} = a_{2} - a_{1}.

To find the nth term of the sequence, this equation can be written as:

a_{n} = a_{1} + (n-1)d

27,11, -5

So a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d

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3 0
2 years ago
Trigonometry
quester [9]

Answer:

\frac{9 + 2 \sqrt{3} }{3} \\

Step-by-step explanation:

\cosec(30)  +  \cosec(60)  +  \cosec(90)  \\   \\  = 2 +  \frac{2}{ \sqrt{3} }  + 1 \\  \\  =  \frac{2 \sqrt{3 }  + 2}{ \sqrt{3} }  + 1 \\  \\  =  \frac{2 \sqrt{3}  + 2 +  \sqrt{3} }{ \sqrt{3} }  \\  \\  =  \frac{3 \sqrt{3}  + 2}{ \sqrt{3} }  \\  \\  = \frac{3 \sqrt{3}  + 2}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }  \\  \\  =  \frac{9 + 2 \sqrt{3} }{3}

4 0
3 years ago
Read 2 more answers
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labwork [276]

Answer:

Find the values of x and y

X =60

Y=60

60°

3 0
2 years ago
Never mind. I meant these problems. Please find the mean, median, and mode.
Sergio [31]
Median mean to find the center of the data
8 0
3 years ago
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