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mote1985 [20]
3 years ago
8

What is x − 2 y − 2 = 0 in slope intercepct form?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

y=1/2x-1

Step-by-step explanation:

hope this helps

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3/4x - 7/12 + 7/24x + 2/3 - 1/6x simplify
n200080 [17]

Answer:

Step-by-step explanation:

=7/8x+11/2

Hope this helps

Mark me as brainiest

3 0
3 years ago
Helppppppppppppppppppppp
Alex_Xolod [135]

Answer:

\frac{ {x}^{2} +  - 4x - 2 }{ {x}^{2} - 4 }  +  \frac{8x + 6}{{x}^{2} - 4}  \\ =  \frac{ {x}^{2} +  - 4x + 8x - 2 + 6 }{ {x}^{2} - 4 } \\ =  \frac{ {x}^{2} +   4x  +  4 }{ {x}^{2} - 4 } \\  =  \frac{ {(x + 2)}^{2} }{(x - 2)(x + 2)}  \\  =  \frac{x + 2}{x - 2}

5 0
3 years ago
What is 6 divided by 258?
Andreas93 [3]
258 / 6 = 43

Hope this helps!
7 0
3 years ago
Read 2 more answers
The graph shows a point at (4,1) and a line segment with endpoint at (2,2) and (6,2) This line segment will be dilated with the
Mamont248 [21]

Dilation involves changing the size of a figure

The endpoints of the image are (0,3) and (8,3)

<h3>How to determine the coordinates of the image</h3>

The coordinates of the pre-image are give as:

(2,2) and (6,2)

The scale factor is given as:

k = 2

The center of dilation is given as:

(a,b) = (4,1)

The coordinates of the image are then calculated as:

(x,y) = (k(x -a) + a, k(y -b) + b)

For (2,2), we have:

(x,y) \to  (2(2 -4) + 4, 2(2 - 1) + 1)

(x,y) \to  (0, 3)

For (6,2), we have:

(x,y) \to  (2(6 -4) + 4, 2(2 - 1) + 1)

(x,y) \to  (8, 3)

Hence, the endpoints of the image are (0,3) and (8,3)

Read more about dilation at:

brainly.com/question/3457976

6 0
3 years ago
The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
madam [21]

The true statement is:

"The range of the function is all real numbers less than or equal to 9."

<h3>Which statements are true?</h3>

Here we have the quadratic function:

f(x) = -x^2 - 4x + 5

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

f(x) = -x^2 - 4x + 5

So the vertex is at:

x = 4/(2*-1) = -2\\

Then the y-value of the vertex is:

f(-2) = -(-2)^2 - 4*(-2) + 5 = -4 + 8 + 5 = 9

So the range is the set of all real numbers less than or equal to 9.

So the above statement is false, and the final one:

"The range of the function is all real numbers less than or equal to 9."

Is the true statement.

If you want to learn more about quadratic functions:

brainly.com/question/1214333

#SPJ1

8 0
2 years ago
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