(A) Just because every digit has an equal chance of appearing does not mean that all will be equally represented. (See "gambler's fallacy")
(B) The experimental procedure isn't exactly clear, so assuming a table of digits refers to a table of just one-digit numbers, each with 0.1 chance of appearing (which means you can think of the digits 0-9), you should expect any given digit to appear about 0.1 or 10% of the time.
So if a table consists of 1000 digits, one could expect 7 to appear in 10% of the table, or about 100 times.
Answer:
- 3, -2. -1 , 0 , 1, 2, and 3
when it looks like that it means that it is less then 3
(x+y=31)2
2x-y=11
2x+2y=62
- 2x -y=11
3y=51
y=17
x+17=31
x=14
y-x=3
Answer:
Step 1. The answer is no.
Step 2. The answer is b.
Step-by-step explanation:
I think Step 2 already sort of explains the reasoning behind the answer for step 1.
Hope this helps!
