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motikmotik
3 years ago
12

An airplane's change in altitude before landing in shown in the table. What equation represents this change in altitude

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer

-4,000

Step-by-step explanation:

Just subtract 35,000 and 31,000 or 27,000 and 21,000 and get 4,000. Since the altitude is going down, it'll be negative.

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PLEASE ANSWER FOR EXTRA <br> POINTS ⭐️⭐️⭐️ GIVE BRAINLIST
Andrei [34K]

Answer:

D. all real numbers

Step-by-step explanation:

The domain is all the x's on a graph or that are permitted in an equation (if you have an equation instead of a graph)

If there is nothing on the graph to indicate the graph is a segment (endpoints that are either closed or open) or has other holes in it (literally a point on the line that is open) then the domain for a linear function (a line) is always all real numbers. The same is true for all of the above for the range as well, except the range is all the y's

7 0
2 years ago
Read 2 more answers
2) Two full revolutions = how many degrees? I
VARVARA [1.3K]

Answer:

720 degrees

Step-by-step explanation:

one full rotation is 360 degrees

360 + 360 = 720

5 0
4 years ago
Read 2 more answers
A system of equations is shown below,
Vikki [24]
Answer: No solution
Step by step:
10x-2(5x+2)=12
10x-10x-4=12
0x=16
No solution
4 0
3 years ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
number pattern has 75 as its first term. The rule for the pattern is subtract 6. What is the sixth term
____ [38]
Since you subtract 6 and you have to find the sixth term, you can do:
-6×5=-30 ( negative shows you're subtracting and since 75 is the first term, then you have to find the difference of the input/term 6-1, the sixth term minus the first)
75-30=45
You can check by actually continuing the pattern.
75,69,63,57,51,45,39......
4 0
3 years ago
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