Given equation :−1/2 (x+2) + 112x = 3
We have -1/2 in front of parenthesis on left side .
It's better to remove fraction in an equation, in order make it easier to solve.
In order to remove 2 from denominator of 2, we need to multiply each and every term by 2.
Multiplying each term in the equation by 2, we get
2* −1/2(x+2) +2* 112x = 2*3.
On simplifying this step, we get
-1(x+2) +224x = 6.
Distributing -1 over (x+2), we get
-x -2 +224x = 6
Combining like terms on left side, -x+224x=223x
223x -2 = 6
Adding 2 on both sides, we get
223x -2+2 = 6+2
223x = 8
Dividing both sides by 223, we get
223x/223 = 8/223.
x= 8/223.
Answer:
97,175
Step-by-step explanation:
I don't think It's necessary, but I am gonna do it anyways.
15*6=90
15*7=105
105 - 90 =15
15/2 =7,5
90+7,5= 97,5
15*6,5= 97,5
0,05*6,5= 0,325
97,5 - 0,325 = 97,175
Answer: 6
Explanation:
3 x 2 = 6
V of w sphere =
r³
Multiply by 3 on either sides to get rid of the fraction.
3V = 4
r³
Now divide either sides by 4
to isolate r³
r³
4
and 4
cancels out
= r³
Take the cube root to isolate r.
![\sqrt[3]{ \frac{3V}{4 \pi } } = \sqrt[3]{r^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20%3D%20%20%5Csqrt%5B3%5D%7Br%5E3%7D%20)
the cube root cancels the cube
![\sqrt[3]{ \frac{3V}{4 \pi } }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20)
= r
