Answer:
C.
2.67 inches by 2.27 inches
Step-by-step explanation:
We can use ratios to solve
1 in x inches
-------- = ---------
7.5 ft 20 ft
Using cross products
1*20 = 7.5x
Divide each side by 7.5
20/7.5 =7.5x/7.5
2.67 =x
We can do the same for the other dimension
1 in x inches
-------- = ---------
7.5 ft 17 ft
Using cross products
1*17 = 7.5x
Divide each side by 7.5
17/7.5 =7.5x/7.5
2.27 =x
2.67 inches by 2.27 inches
The question is telling you that the length of the rectangle is 3 metres more than twice the width.
So let:
<em>w= width</em>
<em>L= length</em>
Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>
They also tell you the perimeter is 48 metres.
<em>P= L+L+w+w</em>
So the equation of the perimeter is:
<em>48= (2w+3)+(2w+3)+2w +2w</em>
<em>48= 2(2w+3) + 4w</em>
To find w, expand and simplify.
<em>48= 4w+6+4w</em>
<em>48= 8w + 6</em>
<em>42= 8w</em>
<em>5.25=w</em>
Now that you know the width, plug in the value into the length equation:
<em>L= 2w+3</em>
<em>L=2(5.25)+3</em>
<em>L=10.50+3</em>
<em>L=13.5</em>
If I am wrong let me know! I hope this helps.
In a function, the range is the y value or axis. Most points on this graph have a y value of zero, but one has a value of 1.
The correct answers are 0 and 1.
Hope this helps!
Answer: About 191 students scored between a 60 and an 80.
Step-by-step explanation:
Given : A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5.
i.e. 
and 
let x be the random variable that denotes the test scores.
Then, the probability that the students scored between a 60 and an 80 :
The number of students scored between a 60 and an 80 = 0.9544 x 200
= 190.88 ≈ 191
Hence , about 191 students scored between a 60 and an 80.
