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Vladimir79 [104]

3 years ago

9

A sheet of origami paper is in the shape of a square with a side length of 7 inches, as shown. What is the area of the sheet of

origami paper?
The answer is C!!

I took the unit test, your welcome tehe UwU

2 answers:

vlabodo [156]3 years ago

8 0

??... what lol good job tho

Gnesinka [82]3 years ago

7 0

Answer:

what was c?

Step-by-step explanation:

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Which property of inequality should you use to solve 3x ≤ 27?

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division property would help you solve this inequality

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Which of the following are roots of the polynomial function?

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Answer:

1 and -5

Step-by-step explanation:

$~~~~~x^3+3x^2-9x+5=0\\\\\implies x^3-x^2+4x^2-4x-5x+5=0\\\\\implies x^2(x-1)+4x(x-1)-5(x-1)=0\\\\\implies (x-1)(x^2 +4x -5) = 0\\\\\implies (x-1)(x^2+5x -x -5) = 0\\\\\implies (x-1)[x(x+5) -(x+5)] =0\\\\\implies (x-1)(x-1)(x+5)= 0\\\\\implies (x-1)^2(x+5) = 0\\\\\implies x = 1,~~ x = -5$

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2 years ago

Jesus spent 1/4 of his money on a pizza and 1/4 of his money on salad. What fraction of his money did Jesus spend on dinner?

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Step-by-step explanation:

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3 years ago

Read 2 more answers

How many sides has a regular polygon whose sum of interior angles is 540degrees

Svetllana [295]

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3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago