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Ann [662]
3 years ago
11

Convert the surveyor's bearing 145° to a compass bearing​

Mathematics
1 answer:
Allushta [10]3 years ago
7 0

Answer:

S55°E is the compass bearing

Step-by-step explanation:

145° - 90° = 55°

The bearing will be in between South and East because from North to South is 180° and 145° is bigger than 90°

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HELP PLEASE! Find the standard deviation for Data set 1 and 2. round to the nearest hundred. DATA SET ONE: 8.2, 11.6 8.7, 10.6,
Elan Coil [88]

Answer:

0.92 and 1.25 respectively

Step-by-step explanation:

0.92 and 1.25 respectively

first the mean of each value which is 9.7 and 9.8 respectively

standard deviation = square root of the mean deviation of each value

then deduct the mean from each element

and square each value and add them together. not you should square each deviation value before you add them

at last divide the result by the number of frequency and find it's square root

3 0
3 years ago
They Yankees won 90 of their 162 games last season. What percent of the games did they win?​
LUCKY_DIMON [66]

Answer:

55.6%

Step-by-step explanation:

The fraction 90/162 in its decimal equivalent is 0. 556.  Multiplying this by 100 yields the percentage 55.6%.

5 0
3 years ago
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Simplify (x+5)(x+5)(x+5)​
Deffense [45]
3x + 15 because u add all the x and then all real numbers
5 0
2 years ago
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Find the velocity, v(t), for an object moving along the x-axis if the acceleration, a(t), is a(t) = 3t^2 + cos(t) and v(0) = 2.
Scorpion4ik [409]
\bf \displaystyle a(t)=3t^2+cos(t)\implies \stackrel{velocity}{\int~ [3t^2+cos(t)]dt}\\\\\\ t^3+sin(t)+C=~~~v(t)
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\begin{cases}
v(0)=2\\
v=2\\
t=0
\end{cases}\implies 0^3+sin(0)+C=2\implies C=2
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6 0
3 years ago
Find the distance between the points.<br> (0,4) and (-3,4)<br> The distance is
Inessa [10]
<h3>Answer:  3 units</h3>

=============================================================

Explanation:

The y coordinates are identical, so we just need to focus on the x coordinates.

Going from 0 to -3 is a distance of 3 units. Drawing out a number line might help.

Or we could apply subtraction and absolute value

|x1-x2| = |0-(-3)| = |0+3| = |3| = 3

which is the same as

|x2-x1| = |-3-0| = |-3| = 3

The absolute value is to ensure the result is never negative. Distance is never negative.

Side note: if the y coordinates weren't the same, then we'd have to use either the pythagorean theorem or the distance formula.

4 0
2 years ago
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