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Ann [662]
2 years ago
11

Convert the surveyor's bearing 145° to a compass bearing​

Mathematics
1 answer:
Allushta [10]2 years ago
7 0

Answer:

S55°E is the compass bearing

Step-by-step explanation:

145° - 90° = 55°

The bearing will be in between South and East because from North to South is 180° and 145° is bigger than 90°

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the volume of a sphere whose diameter is 18 centimeters is ? cubic centimeters. If its diameter were reduced by half its volume
Ghella [55]
A) The formula for the volume of a sphere in terms of its radius (half the diameter) is
V= \frac{4}{3}\pi r^{3}
For your 18 cm sphere, the volume is
V= \frac{4}{3}\pi(9 cm)^{3} = 972\pi \cdot cm^{3} \approx 3054 cm^{3}

B) If the diameter were reduced by half, the volume would be (\frac{1}{2})^{3}=\frac{1}{8} of the original volume.
7 0
3 years ago
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A marketing research company needs to estimate the average total compensation of CEOs in the service industry. Data were randoml
mezya [45]

SOLUTION:

Step 1 :

In this question, we are told that a marketing research company needs to estimate the average total compensation of CEOs in the service industry.

We also have that: Data were randomly collected from 38 CEOs and the 98% confidence interval was calculated to be ($2,181,260, $5,836,180).

Then, we are asked to find the margin error for the confidence interval.

Step 2:

We need to recall that:

\text{Higher Confidence Interval, CI}_{H\text{ = }}X\text{ + }\frac{Z\sigma}{\sqrt[]{n}}\text{Lower Confidence Interval , CI}_{L\text{ }}=\text{ X - }\frac{Z\sigma}{\sqrt[]{n}}

It means that:

\vec{}X\text{ = }\frac{CI_{H\text{ }}+CI_L}{2}\text{Margin of error, }\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{CI_{H\text{ - }}CI_L}{2}

where,

CI_H\text{ = }$$5,836,180$\text{ }$$$CI_{L\text{ }}=\text{ }2,181,260

putting the values into the equation for the margin of error, we have that:

\text{Margin of error,}\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{5,836,180\text{  - }2,181,260\text{ }}{2}\begin{gathered} =\text{ }\frac{3654920}{2} \\ =1,\text{ 827, 460} \end{gathered}

CONCLUSION:

The margin error for the confidence interval is 1, 827, 460

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Can anybody help? i’m super confused
vaieri [72.5K]

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