10=2x5
60=2x2x3x5
2x2x5x3=60
i think to do this you need lcm but im not sure
Answer:
0.01 is the awnser can you put me as the brainlest awnser
Step-by-step explanation:
Answer:
314 is the correct answer
Step-by-step explanation:
314 is the correct amswer to 628 ÷ 2, however, the answer to 2 ÷ 628 is invalid and would need to be simplified.
The factored expression which represents the net change in the number of blog subscriptions over 10 months is :
- 3(11 - 7) + 4(-8)
- Hence, the net change is -20
Change : -8, 11, -7, -7, -7, -8, -8, -8, 11, 11
To factor the values in the change variable :
-7 has a frequency of 3
-8 has a frequency of 4
11 has a frequency of 3
Values having the same frequency can be factored together :
Hence, we have ;
3(11 - 7) = 3(11 - 7) = 3(4) = 12 - - - - (1)
-8 having a value of 4 can be factored thus ; 4(-8) = -32 - - (2)
Joining both equations :
3(11-7) + 4(-8)
3(11 - 7) + 4(-8)
3(4) + 4(-8)
12 + (-32)
= - 20
Therefore, the factored expression for the net change in subscription is 3(11-7) + 4(-8)
Learn more :brainly.com/question/18904995
Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
