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Sav [38]
2 years ago
9

A company uses tow vans to transport workers from a free parking lot to the workplace between 7:00 and 9:00 a.m. one van has 6 m

ore seats than the other. the smaller van makes two trips every morning while the larger one makes only one trip. the two vans can transport 57 people maximum.
y seats in the large van. how many seats does the larger van have?
Mathematics
1 answer:
sladkih [1.3K]2 years ago
7 0
The large van has 23 seats and the small van has 17 seats

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What is -2 × 1 1/4=
RoseWind [281]

Answer: -11/2

Step-by-step explanation:

Just set it up so it looks like this:

-2/1 x 11/4 and multiply across the top, which would be -22 and then the across the bottom, which would equal 4. So it’s -22/4. BUT you can simplify it down to -11/2 by dividing both sides of the fraction by 2. So then answer is -11/2

Hope that makes sense! :)

5 0
2 years ago
Jane has a 5 × 7-inch photograph that she wants enlarged to a 10 × 14-inch photograph. What is the scale factor from the origina
Vladimir79 [104]
I think that the answer is 2, because if you multiply two by each factor in the original photograph then you get the size of the new photograph.
5 0
2 years ago
Read 2 more answers
(x/16)-(x+2)/8))=2<br><br><br><br> PLS HELP ME BRAINLIEST TO THE FIRST CORRECT ANSWER
ArbitrLikvidat [17]

Simplify both sides of the equation

x/16−(x+2/8) = 2x/16 + −1/8x + −1/4 = 2

Distribute

1/16x + −1/8x + −1/4 = 2

(1/16x + −1/8x)+(−1/4) = 2

Combine Like Terms

−1/16x + −1/4 = 2

Add 1/4 to both sides.

−1/16x + −1/4 + 1/4 = 2 + 1/4

−1/16x = 9/4

Multiply both sides by 16/(-1).

(16/−1)*(−1/16x)=(16/−1)*(9/4)

x=−36

3 0
2 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
3 years ago
Select the correct answer.
Semenov [28]

Answer:

The last option: 3 x (7 + 2) = (3 x 7) + (3 x 2)

Step-by-step explanation:

There is addition on the inside, and you are distributing the multiplication from the outside.

3 0
3 years ago
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