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Semenov [28]
3 years ago
13

Please help me solve this question thank you​

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

Step-by-step explanation:

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Picture of problem below NO LINKS
iragen [17]

Answer:

600$

Step-by-step explanation:

I think this is right

5 0
3 years ago
Fred has 230 animals at his zoo. Grace at 349 more animals in her zoo than Fred has. how many animals do they have altogether? T
WARRIOR [948]

Step-by-step explanation:

okay so im in 8th grade and i just worked the problem out and i got , 809 ,

first you add 230 + 349 to see how much she has in her farm

she has 579, then you add 579 because she has that many , and he has 230 so you add 579 +230 and tou get 809

work:

230

+349

----------

579

+230

---------

809

hope i helped!!

4 0
3 years ago
The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3
Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is 258.75\ in^3.

Given:

Length = Height - 4 = h - 4

Width = 3 in

We need to find the height of the box.

Solution:

We know that the volume of the box.

Volume = Length\times height\times width

Substitute all given value in above formula.

258.75 = (h-4)\times h\times 3

Rewrite the equation as:

258.75 = 3h(h-4)

258.75 = 3h^2-12h

3h^2-12h-258.75=0

whole equation divided by 3.

h^2-4h-86.25=0

Use quadratic formula with a = 1, b = -4,c=-86.25

h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}

Put these a, b and c value in above equation.

h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}

h=\frac{4\pm \sqrt{16+345}}{2}

h=\frac{4\pm \sqrt{361}}{2}

h=\frac{4\pm 19}{2}

For positive sign

h=\frac{23}{2}  

h = 11.5 in

For negative sign

h=\frac{-15}{2}

h = -7.5

We take positive value of h.

Therefore, the height of the box h = 11.5 in

4 0
3 years ago
Will give you brilliantest
Zina [86]
I don’t know but maybe 2
6 0
2 years ago
Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
3 years ago
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