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gizmo_the_mogwai [7]

3 years ago

10

Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average. Margie wants to k

now the estimated probability that her first serve will be good at least four of the next six times she serves. How could she design a simulation for this scenario?

2 answers:

mojhsa [17]3 years ago

7 0

Answer:

0.6804

Step-by-step explanation:

Given that Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average.

Since each trial is independent and there are two outcomes, X no of good serves is binomial with n=6 and p =2/3

Required probability

= Prob that atleast four of 6 times good serve

= $P(X\geq 4)$

= $P(x=4,5 or 6)\\=1-F(3)\\=0.6804$

Formula used:

P(X=r) = $6Cr (\frac{2}{3}^r )(\frac{1}{3}^{6-r} )$

satela [25.4K]3 years ago

3 0

What even does the other guy mean that didnt help at all.

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Find the unknown side length of the rectangle is 3 2/3 and if the area is 11m2

patriot [66]

Answer:

The width of the rectangle given is equal to 3m.

Step-by-step explanation:

In order to solve this question we need to know that the areas of the rectangle is equal to $A_{rectangle} = (l)(w)$ , where "l" is length and "w" is width. So know in order to solve this question we would have to find out the unknown width by using area and the length of the triangle. Based on the formula I wrote down earlier we can understand the following.....

$A_{rectangle} = (l)(w)$

$\frac{A_{rectangle} }{l} = \frac{(l)(w)}{l}$

$w = \frac{A_{rectangle} }{l}$

Just now we found out the formula that we can use to solve for the width when we know the area and the length of the rectangle. Now in order to get the answer we just have to plug in the values we know, and we get........

$w = \frac{A_{rectangle} }{l}$

$w = \frac{11m^{2} }{(3\frac{2}{3}m )}$

$w = 3m$

7 0

3 years ago

What is the value of 0 in the number 9,603,450,503

asambeis [7]

Answer:

0

Step-by-step explanation:

0 x 10

0 x 1000

0 x 10 000 000 they all equal 0

4 0

2 years ago

Someone please help me with this

NeX [460]

I hope this helps you

4 0

4 years ago

Police records in the town of Saratoga show that 17 percent of the drivers stopped for speeding have invalid licenses. If 24 dri

Ymorist [56]

Answer:

Step-by-step explanation:

Given

17 % of the drivers stopped have invalid licenses

n=24 drivers are stopped

using Binomial distribution

$^nC_r(p)^r(q)^{n-r}$

here p=0.17

q=1-0.17=0.83

(a)none will have valid license i.e. r=0

$P(r=0)^{24}C_0(0.17)^0(0.83)^{24}=(0.83)^{24}=0.0114$

(b)Exactly one have invalid license i.e. r=1

$P(r=1)=^{24}C_1(0.17)^1(0.83)^{23}=24\times 0.17\times (0.83)^{23}$

$=0.0561$

(c)At least 2 will have invalid license i.e. $r\geq 2$

$P(r\geq 2)=1-P(r=0)-P(r=1)$

$P(r\geq 2)=1-0.0114-0.0561$

$P(r\geq 2)=0.932$

3 0

3 years ago

the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room

Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

$C.S.A.=2h(l+b)$

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

$C.S.A.=\text{Perimeter of the base} \times h$

Putting the given values, we get

$C.S.A.=18\times 3$

$C.S.A.=54$

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0

3 years ago