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gizmo_the_mogwai [7]
2 years ago
10

Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average. Margie wants to k

now the estimated probability that her first serve will be good at least four of the next six times she serves. How could she design a simulation for this scenario?

Mathematics
2 answers:
mojhsa [17]2 years ago
7 0

Answer:

0.6804

Step-by-step explanation:

Given that Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average.

Since each trial is independent and there are two outcomes, X no of good serves is binomial with n=6 and p =2/3

Required probability

= Prob that atleast four of 6 times good serve

=P(X\geq 4)

=P(x=4,5 or 6)\\=1-F(3)\\=0.6804

Formula used:

P(X=r) =6Cr (\frac{2}{3}^r )(\frac{1}{3}^{6-r}  )

satela [25.4K]2 years ago
3 0

What even does the other guy mean that didnt help at all.

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WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
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Seven out of every twenty soda bottles produced have caps indicating that the purchaser has won a prize. Which equation represen
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Step-by-step explanation:

35

7 0
2 years ago
Allison measured a line to be 19.4 inches long. If the actual length of the line is 19.1
Lelu [443]

It can be noted that the percentage error made by Allison will be 1.6%

<h3>How to solve the percentage</h3>

From the information given, Allison measured a line to be 19.4 inches long and the actual length of the line is 19.1.

Therefore, the percentage error will be:

= (19.4 - 19.1)/19.1 × 100

= 0.3/19.1 × 100

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In conclusion, the correct option is 1.6%.

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2 years ago
Find the distance between the points (-5,6) and (3,2)<br> round to the nearest hundred​
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Step-by-step explanation:

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3 0
2 years ago
Cholesterol levels for a group of women aged 30-39 follow an approximately normal distribution with mean 190.14 milligrams per d
Anettt [7]

Answer:

Step-by-step explanation:

Hello!

X: Cholesterol level of a woman aged 30-39. (mg/dl)

This variable has an approximately normal distribution with mean μ= 190.14 mg/dl

1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:

P(Z≥z₀)= 0.093

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Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:

P(Z≤z₀)= 0.907

Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:

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2.

Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:

Z= (X- μ)/δ ~N(0;1)

Z= (X- μ)/δ

Z*δ= X- μ

δ=(X- μ)/Z

δ=(240-190.14)/1.323

δ= 37.687 ≅ 37.7 mg/dl

I hope it helps!

8 0
3 years ago
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