Answer:
A = 58 degrees
b = 51.9
c = 48.5
Step-by-step explanation:
To find A we simply just need to remember that all triangles add up to 180 degrees and we are already given two angles of the triangle so....
To find sides b and c we use the law of sines since we now know the angle of each side.
Hope this helps.
Here is an example, if the graph hovers above the x-axis (k<0) then there will be no real solutions
Answer:
m∠QPR = 35° m∠QPM =40° m∠PRS = 30°
Step-by-step explanation:
ΔPRQ is a right triangle with right angle at R. So m∠QPR = 90 - 55 = 35
ΔQPM is a right triangle with right angle at M. So m∠QPM = 90 - 40 = 40
Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.
So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60
Now arc PS is the intercepted arc for ∠PRS.
Therefore, m∠PRS = 60/2 = 30
I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times. Also, I used the fact that the acute angles of a right triangle are complementary. And, finally I used the fact that an inscribed angle in a semicircle is a right angle.
I hope this helped.
Answer:
The correct one is 6 power7