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3 years ago

88th term of the sequence 4,-1,-6

Mathematics

1 answer:

MArishka [77]3 years ago

4 0

Answer:

-431

Step-by-step explanation:

4-5=-1 -1-5= -6 common difference is -5 and start at 4 to get 88th term which is -431

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A line that includes the point (2,10) has a slope of 9. What is its equation in slope-intercept form

Bumek [7]

Equation: y= 9x+ (y-intercept)

Step-by-step explanation:

equation in slope-intercept form is y=mx+b. m represents the slope of the line, and b represents the y=intercept, which is where the line crosses the y-axis.

3 0

3 years ago

Tristán wants to build a square garden in his backyard if the garden is going to be 64 ft2 how many feet of material will he nee

Alex777 [14]

Answer:

Tristan will need 32 feet of material for the perimeter of the garden.

Step-by-step explanation:

Given that

Area of square garden = A = 64 square feet

Perimeter = P = ?

We know that for calculation of perimeter, length of side of square is required which is not directly given in the question. The area will be used to calculate length of side and then length will be used to calculate the perimeter.

So,

$Area = A = s^2$

s is for side

Putting the value of area

$64 = a^2$

Taking square root on both sides

$\sqrt{s^2} = \sqrt{64}\\s = 8\ feet$

The length of side is 8 feet.

Perimeter will be:

$P = 4*s\\P = 4*8\\P = 32\ feet$

Hence,

Tristan will need 32 feet of material for the perimeter of the garden.

3 0

3 years ago

What is the simplest form of the expression below? -2x²(3x²-2x-6)

nirvana33 [79]

Answer:

Solution Given:

To find the simplest form we need to open bracket

-2x²(3x²-2x-6)

-2x²*3x²-2x²*(-2x) -2x²*(-6)\

$-6x^{4}+4x^{3}+12x^2$ is a required answer.

7 0

2 years ago

I need help asap plz!!!

svet-max [94.6K]

Answer:

AC ≈ 10.3

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan48° = $\frac{opposite}{adjacent}$ = $\frac{AC}{AB}$ = $\frac{AC}{9.3}$ ( multiply both sides by 9.3 )

9.3 × tan48° = AC , then

AC ≈ 10.3 ( to 3 sf )

5 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago