What is the slope of a line parallel to the line -3x+5y=-10

Mathematics

2 answers:

lapo4ka [179]3 years ago

4 0

This looks familiar, right? Like slope-intercept.

y=mx+b, where m is the slope.

Let's right it like that.

5y=3x-10 (add 3x to both sides, since we want to isolate the y.)

Now divide by 5, since - again - we want to isolate the y.

y= 3/5x-10/5 >>>> y= 3/5x-2

I think the slope is 3/5.

If the line happens to be parallel, the slope is the same. If perpendicular, it is opposite reciprocal. So if it was perpendicular, the slope would be -5/3.

max2010maxim [7]3 years ago

3 0

The slope can be found re-writting the function in the general format s y=mx+n where m is known as slope. For this case:

-3x+5y=-10, trasponding the x term

5y=3x-10, dividing by 5

y=3x/5-10/5, solving finally have the general format:

y=3/5x-2

Then the slope is the number that precede the x unknow.

Solution. The slope is 3/5.

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Masja [62]

Answer:

Solving the expression $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$ we get 6

The answer is 6.

Step-by-step explanation:

We need to find value of expression: $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$

We know that $\sqrt{81}=9$

Our expression will become

$\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4$