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3 years ago

10

Un polígono regular está inscrito en una circunferencia. ¿Qué medida del polígono es igual al radio de la circunferencia?

1 answer:

vlabodo [156]3 years ago

4 0

Answer:

La medida del polígono que es igual al radio de la circunferencia es el segmento de recta comprendido entre el centro geométrico del polígono y cualquiera de sus vértices, cuyo nombre es también <em>radio</em>.

Step-by-step explanation:

La medida del polígono que es igual al radio de la circunferencia es el segmento de recta comprendido entre el centro geométrico del polígono y cualquiera de sus vértices, cuyo nombre es también <em>radio</em>.

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I need help with this problem! Please Help<br> t=-2.74 + sqrt(2.74^(2)-4*-4.9*(-10)) -: 2*-4.9

Ulleksa [173]

Answer:

Step-by-step explanation:

t=(-2.74 + sqrt(2.74^(2)-4*-4.9*(-10))) / -2*-4.9

t=(-2.74 + sqrt(7.5076-4*+49))/9.8

t=(-2.74 + sqrt(7.5076+45))/9.8

t=(-2.74 + sqrt(52.5076))/9.8

t=(-2.74/9.8)+(sqrt(52.5076))/9.8

this is simplest form, next will be rounded answers

t=0.45981763305

3 0

3 years ago

Read 2 more answers

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

Convert 76,000 ml into L. Please show your work.

ser-zykov [4K]

Ok so there are 1,000 ml in every liter so
76000 ml= L which is a thousand ml
76000/1000
=76 L

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3 years ago

36. The price of a new home. According to the U.S. Census

zmey [24]

Answer:

210

Step-by-step explanation:

because you use 13.% divided by the price

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3 years ago

Who was the first president of Latvia?

Sav [38]

Answer:

Jānis Čakste

Step-by-step explanation:

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3 years ago

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