Answer:
The sample size needed is 2401.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error of the interval is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.
We have to find n, for which M = 0.02.
There is no estimate of p available, so we use 
The sample size needed is 2401.
While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that a digit in the ten thousand place values ten times what the same digit values is it is the thousand place.
All you have to do is divided 43.54 divided by 3.5 which is 12.44 mph
1) 8
2) 14.5*2=29
3) 7x+5=2*13, 7x+5=26, 7x=21, x=3
4)d(1)=2r,
if r increase 3 times, d(2)=2*(3r)
d(2)/d(1)=(2*3r)/2r=3,
so diameter increases 3 times
