What we know so far:
Side 1 = 55m
Side 2 = 65m
Angle 1 = 40°
Angle 2 = 30°
What we are looking for:
Toby's Angle = ?
The distance x = ?
We need to look for Toby's angle so that we can solve for the distance x by assuming that the whole figure is a SAS (Side Angle Side) triangle.
Solving for Toby's Angle:
We know for a fact that the sum of all the angles of a triangle is 180°; therefore,
180° - (Side 1 + Side 2) = Toby's Angle
Toby's Angle = 180° - (40° + 30°)
Toby's Angle = 110°
Since we already have Toby's angle, we can now solve for the distance x by using the law of cosines r² = p²+ q²<span>− 2pq cos R where r is x, p is Side1, q is Side2, and R is Toby's Angle.
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x² = Side1² + Side2² - 2[(Side1)(Side2)] cos(Toby's Angle)
x² = 55² + 65² - 2[(55)(65)] cos(110°)
x² = 3025 + 4225 -7150[cos(110°)]
x² = 7250 - 2445.44
x = √4804.56
x = 69.31m
∴The distance, x, between two landmarks is 69.31m
The addition property of equality. It says that if you add the same number to each side of the equation, the two sides of the equation will be equal. In this case, the number 8 was added to each side.
Hope this helps :)
Answer:
540, 541, 542
Step-by-step explanation:
let the number be n
hence the 3 consecutive numbers may be expressed as:
n , n+1, n+2
it is given that the sum of the 3 numbers is 1623
hence,
n + (n+1) + (n+2) = 1623
n + n + 1 + n + 2 = 1623
3n + 3 = 1623
3n = 1623 -3
3n = 1620
n = 1620 / 3
n = 540
hence the numbers are
540, (540 + 1) , (540 + 2)
or
540, 541, 542
Answer:
Step-by-step explanation:
Let the required volume be x
<u>Use the ratio of gallon/volume to solve:</u>
- 1/0.13 = 20/x
- x = 20*0.13
- x = 2.6 ft³
With 20 gallons the scientist can cover 2.6 ft³ of water volume
Answer:
Option(b) is the correct answer to the given question
Step-by-step explanation:
1) If 
then , there must be a positive Autocorrelation
According to it if the ratio d of durbin-watson is equal to or less than dL then it is called as Positive Autocorrelation.
2 ) if , then it is Inconclusive
According to it If the coefficient d of the Durbin-Watson is between dL & du then it is called as Inconclusive.
3) if 
then there is No proof of the Autocorrelation
According to it if the d of the durbin-watson will be less than or equivalent to du then it is called as No Autocorrelation.
4) If 
) then there is No proof of the Autocorrelation
According to it if the d of the durbin-watson will be less than or equivalent to 4- du then it is called as No Autocorrelation.
5) If the 
, then it is Inconclusive
According to it if the d of the durbin-watson is between the 
then it is called as Inconclusive.
6) If the 
then it called as negative Autocorrelation
According to it if the d of the durbin-watson is greater then 
then it is called as negative autocorrelation.
- From the point 6 we can say that the option(B) is correct
- All the others options are not correct for (4 − dL), so these are incorrect option .
