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Step2247 [10]
3 years ago
15

(10

Mathematics
2 answers:
rewona [7]3 years ago
7 0

Answer:

2 by 1

Step-by-step explanation:

2 by 1

Anni [7]3 years ago
6 0

Given:

The matrix multiplication

\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is m_1\times n_1 and the order of second matrix is m_2\times n_2, then the order of these two matrices is m_1\times n_2.

We have,

\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}

Here, the order of first matrix is 2\times 3 and the order of the second matrix is 3\times 1. So, the order of the second matrix is 2\times 1. It is also written are 2 by 1.

Therefore, the correct option is A.

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