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nevsk [136]
3 years ago
6

Solving a Multi-Step Equation

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0
Your answer will be 15 no need to thank me
VLD [36.1K]3 years ago
5 0

Answer:

x = 15

Step-by-step explanation:

I have this all put under a photo. Let me know if you need any explanation

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How do i solve this?
alina1380 [7]

Answer:

x=3

Step-by-step explanation:

minus 3x on both sides

after you've subtracted 3x from both sides you then need to minus 12 from both sides

Last step is going to be dividing by 2 and you should get the answer of 3

8 0
3 years ago
Read 2 more answers
Can someone do eight nine one and two ?
Sergeeva-Olga [200]

Answer: hello there here are your answers:

8) B multiplication property of zero

9) C additive identify

1) 8

2) -2a-7

Step-by-step explanation:

1) \frac{3+u}8^{2}  \\u=5 \\so\\ \frac{3+5}8^{2}  \\3+5=8^{2} \\8^{2} =\\64 \\\\ 64/8=\\\\\\8 \\there.\\\\\\

2)-2(a-7)\\\\-2(a)(-7)\\\\=-2a+14\\\\\\there

5 0
2 years ago
Given the equation y = 2 x - 8, what is the slope and the y -intercept?
jeka94

Answer:

m=2 and b=-8

Step-by-step explanation:

This equation is organized in slope-intercept form, y=mx+b. In this form, m is the slope and b is the y-intercept.

When given the equation, y=2x-8, we can see that 2 is in the place of m and -8 is in the place of b. The reason the y-intercept isn't 8 is that y=2x-8 can be written as y=2x+(-8) since y=mx+b involves addition. Therefore, the slope is 2 and the y-intercept is -8.

m=2 and b=-8

I hope this helps!

4 0
2 years ago
When are x+3 and 2x equal? When are they not equal? Use your diagrams to explain.
Tanzania [10]
Yes hope this helps :)


4 0
2 years ago
Which of the following are identities? Check all that apply
Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}

Double angle tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula sin2\alpha =2sin\alpha *cos\alpha

sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)

D) False No further development towards a Trig Identity

[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)

7 0
3 years ago
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