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andrew-mc [135]
3 years ago
5

Pls help w explanation!!!

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0

Answer:

The possible values of W are 5, 6, and 7.

Step-by-step explanation:

Since at her gym, Ximena spends 30 minutes on each aerobic workout and 20 minutes on each weight-lifting workout, and last week, Ximena spent between 190 and 230 minutes, inclusive, on 3 aerobics workouts and W weight-lifting workouts, to determine what is one possible value of W the following calculation must be performed:

190 - (3 x 30) = X

190 - 90 = X

100 = X

100/2 = 5

140/2 = 7

Therefore, the possible values of W are 5, 6, and 7.

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Select the equation that most accurately depicts the word problem. One-half of a certain number is 95. - n = 95 + n = 95 • n = 9
Dahasolnce [82]

Answer:

n * \frac{1}{2} = 95

Step-by-step explanation:

Required:

Select the equation that most accurately depicts the word problem

One-half of a certain number is 95.

Take the certain number to be n.

This statement in equation form will be:n * \frac{1}{2} = 95

Therefore, the equation that most accurately depicts the word problem is n * \frac{1}{2} = 95

Although your options are incomplete, but this answer is correct.

The * symbol can be replaced with a dot sign

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3 years ago
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The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t
motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = 15.5

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$ s = 0.4957 $

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where \bar{x} is the sample mean and Margin of error is given by

$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample size, s is the sample standard deviation and  is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\

So the required 99% confidence interval is

\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0
4 years ago
What is the sum of the finite arthemetic series (-10)+0+10+20....+130
Ganezh [65]
That would be 20,30,40,50,60,70,80,90,100,110,120,130.    200,150,300,250     
650 + 250 = so the answer would be 900.
4 0
4 years ago
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