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stiv31 [10]
3 years ago
14

"three food trucks are set up at points a, b, and c. each of the three trucks is the same distance from the food distributor. at

which point of concurrency is the food distributor located?"
Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

circumcenter

Step-by-step explanation:

Suppose the three food trucks points a,b,c are joined together in such a way that the form a triangle. The perpendicular bisectors of the triangle are concurrent . The point of concurrency is called <u>circumcenter.</u>

According to the circumcenter theorem the points ( vertices of the triangle  a,b,c) are equidistant from the center D ( point of concurrency) called the circumcenter.

As the food distributor is equidistant from each of the trucks it lies at the circumcenter point of concurrency.

The drawing is just a generalizations to give an idea. It does not show actual bisectors perpendicular.

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Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

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\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

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=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

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x=100

check answers by subbing 100 for x in each equation.

y=20+.20(100)

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7 0
2 years ago
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The sum is 4+13+28 =45

6 0
3 years ago
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