What is the value of the expression i × i²× i³× i⁴
1 answer:
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Step-by-step explanation:
to add or subtract in this case you have to the same common denominator. but what ever you do to the denominator you have to do to the numerator. top = numerator and bottom = denominator.
Answer:
<u>(2) x </u><u> 4</u>
Step-by-step explanation:
Given the sqrt(x), x zero
So, given sqrt(x -4), x -4 0
Now solve for x
x - 4 0
x 4
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
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The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
