A scatter plot containing the point (5, 29) has the regression equation yˆ=5x+2 . What is the residual e when x = 5? Enter your
answer in the box.
e = ?
e = ?
2 answers:
Answer:
The residual e=2 when x = 5.
Step-by-step explanation:
A scatter plot containing the point (5, 29), it means the observed value at x=5 it 29.
The given regression equation is
Substitute x=5 in the above regression equation, to find the predicted value at x=-5.
The formula to find the residual value e is
e = Observed value - Predicted value
Therefore the residual e=2 when x = 5.
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SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm