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nikitadnepr [17]
2 years ago
14

What is the horizontal asymptote of the function? f(x)=3x2^x+4

Mathematics
1 answer:
torisob [31]2 years ago
5 0

The vertical asymptotes of a rational function may be found by examining the factors of the denominator that are not common to the factors in the numerator. Vertical asymptotes occur at the zeros of such factors

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Where are the asymptotes for the following function located? f(x)= 7/ x^2-2x-24
Zarrin [17]
Factor the demoniator:-

x^2 -2x - 24 = (x - 6)(x + 4)

the asymptotes occurs when denominator = 0

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7 0
3 years ago
Read 2 more answers
Fond the area of the shaded sector of circle C to the nearest tenth
Lesechka [4]

Solution

Step 1

Write an expression for the area of sector

Area\text{ (A) = }\frac{\theta}{360}\times\pi\times r^2

Where

θ = 52°

π = 3.14

r = 8cm

Step 2

Find the area of the sector after substitution of values into the formula above.

\begin{gathered} A\text{ =}\frac{52}{360}\times3.14\times8^2 \\ A=29.028cm^2 \end{gathered}

To the nearest tenth the area of the shaded sector of circle C = 29.0cm²

5 0
1 year ago
Look at the photo! Please help
torisob [31]
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Explanation:
3 0
3 years ago
The scores of the first two football games were 28 and
butalik [34]

Answer:

35+28=63

Step-by-step explanation:

hope this helps

4 0
3 years ago
L varies directly with the square of Z. L is 12 when Z is 2. Find the value of L when Z is 4.
kow [346]

Answer:

L = 48

Step-by-step explanation:

Given that L varies directly with Z² , then the equation relating them is

L = kZ² ← k is the constant of variation

To find k use the condition L = 12 when Z = 2 , then

12 = k × 2² = 4k ( divide both sides by 4 )

3 = k

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When Z = 4 , then

L = 3 × 4² = 3 × 16 = 48

7 0
3 years ago
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