Answer: The cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.
Step-by-step explanation:
Let x be the cost of one sandwich and y be the cost of one cup of coffee.
By considering the given situation, we have the following equations :-

Multiply 2 on both sides of equation (2) , we get

Subtract equation (1) from equation (3), we get

Put value of y in (1), we get

Hence, the cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.



with that template in mind

notice, in g(x)
B = 1, no change from parent
C= +2
Answer:
100°
Step-by-step explanation:
I assume the image is the one attached below.
The shapes are quadrilaterals, so their interior angles add up to 360°. Three of those angles are 86°, 41°, and 133°. So the fourth angle is:
x + 86° + 41° + 133° = 360°
x = 100°
Answer:
the answer is 24
Step-by-step explanation:
68-38 = 24
Answer:
use a calculator the variable is the angle of a triangle
Step-by-step explanation: