You answer should be 11:35 if i did the math correctly
Answer:
A. G'(5) = 20
B. G'(5) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Derivative Rule [Quotient Rule]: ![\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5D%3D%5Cfrac%7Bg%28x%29f%27%28x%29-g%27%28x%29f%28x%29%7D%7Bg%5E2%28x%29%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
[Given] F(5) = 4, F'(5) = 4, H(5) = 2, H'(5) = 3
[Given] A. G(z) = F(z) · H(z)
[Given] B. G(w) = F(w) / H(w)
[Find] G'(5)
<u>Step 2: Differentiate</u>
A. G(z) = F(z) · H(z)
- [Derivative] Product Rule: G'(z) = F'(z)H(z) + F(z)H'(z)
B. G(w) = F(w) / H(w)
- [Derivative] Quotient Rule: G'(w) = [F'(w)H(w) - F(w)H'(w)] / H²(w)
<u>Step 3: Evaluate</u>
A. G'(5)
- Substitute in <em>x </em>[Function]: G'(5) = F'(5)H(5) + F(5)H'(5)
- Substitute in function values: G'(5) = 4(2) + 4(3)
- Multiply: G'(5) = 8 + 12
- Add: G'(5) = 20
B. G'(5)
- Substitute in <em>x</em> [Function]: G'(5) = [F'(5)H(5) - F(5)H'(5)] / H²(5)
- Substitute in function values: G'(5) = [4(2) - 4(3)] / 2²
- Exponents: G'(5) = [4(2) - 4(3)] / 4
- [Brackets] Multiply: G'(5) = [8 - 12] / 4
- [Brackets] Subtract: G'(5) = -4 / 4
- Divide: G'(5) = -1
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
It would be perpendicular
Your answer to 2/3x-4= -2 would be
x=3, or letter D
<span>a=<span><span><span>bx</span>+<span>cx</span></span>+<span><span>
[email protected]</span>x</span></span></span><span>a=<span><span><span>bx</span>+<span>cx</span></span>+d</span></span>Solve for: Let's solve for a.<span>a=<span><span><span>bx</span>+<span>cx</span></span>+d</span></span>Answer:<span>a=<span><span><span>bx</span>+<span>cx</span></span>+d</span></span>