Please help me to find the %

Select all that are true for g(x) = 10/x (PLEASE ANSWER FAST ILL LOVE YOU FOREVER)

Ksivusya [100]

The given function is:

$g(x)= \frac{10}{x}$

The parents functions of g(x) will be:

$f(x)= \frac{1}{x}$

The domain of g(x) and its parent function is the same i.e. Set of all Real numbers except 0.

The range of g(x) and its parent function is the same i.e. set of all real numbers except 0.

g(x) and its parent function only decrease. They do not increase over any interval. However, the interval in which they decrease is the same for both.

So, the correct answers are:
The domain of g(x) is the same as the domain of the parent function.
The range is the same as the range of the parent function.
The function g(x) decreases over the same x-values as the parent function.

8 0

2 years ago

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What is 7/10 divided by 12 simplified

defon

Answer:

7 /120

Step-by-step explanation:

7/10 ÷ 12

Copy dot flip

7/10 * 1/12

7 /120

4 0

2 years ago

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Solve the following equation when a = 3 and b = 2. 5a^2 − 10b + 9b =

rusak2 [61]

The answer for this problem is 43

4 0

2 years ago

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6y + 2x = 24 and 2y – x = -2

Vladimir [108]

( 6 , 2)

in other words :
x = 6 , y = 2

7 0

2 years ago

To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t

ivolga24 [154]

Answer:

$p_v =P(t_{(29)}>1.42)=0.0831$

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:

Null hypothesis: $\mu \leq 100$

Alternative hypothesis: $\mu > 100$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic calculated for this case $t_{calc}= 1.42$

The degrees of freedom are given by:

$df=n-1=30-1=29$

Now we can find the p value using tha laternative hypothesis and we got:

$p_v =P(t_{(29)}>1.42)=0.0831$

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

5 0

3 years ago