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Bumek [7]
3 years ago
15

Please help me to find the %

Mathematics
1 answer:
Viktor [21]3 years ago
8 0
1.068 * 60 - 18.39 =?
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Find an equation of line with given slope and y-intercept. Slope= -6 y-intercept= (0,-10) The equation of the line is: ?
GREYUIT [131]

Step-by-step explanation:

so, we find the slope-intercept form :

y = ax + b

"a" is the slope (it is always the factor of x), "b" is the y-intercept (the y-value when x = 0).

we have the slope : -6

and the given point (0, -10) gives us already the y-value when x = 0 : -10

therefore, the equation is

y = -6x - 10

4 0
1 year ago
Using the rules for special cases, what is the result of?
Arlecino [84]

Answer:

C) 4x^2 -8x +4[/tex]

Step-by-step explanation:

(-2x+2)^2

we apply (a+b)^2 formula

(a+b)^2 = a^2 + 2ab +b^2

a= -2x  and b= 2

Replace 'a' with -2x  and 'b' with 2

(-2x+2)^2 = (-2x)^2 + 2(-2x)(2) +2^2

(-2x)^2 is 4x^2

(-2x+2)^2 = 4x^2 -8x +4

option C is the answer



8 0
3 years ago
Read 2 more answers
How many liters are in 120 kiloliters
Natali [406]
6 is your answer, hope it helped
8 0
3 years ago
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Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance
kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

C^{2}=A^{2}+B^{2}-2ABcos \gamma

so we can solve the formula for C so we get:

C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}

and now we can substitute the values we know:

C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}

C=\sqrt{16+64-32\sqrt{2}}

C=\sqrt{80-32\sqrt{2}} mph

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0
3 years ago
Find the domain and range for the function shown in the<br> graph given below.
Svetllana [295]

Answer:

d{0 less than or equal to x less than or equal to 20, xer}

r{0 less than or equal to y less than or equal to -6,yer}

Step-by-step explanation:

8 0
3 years ago
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