2 years ago

Which three criteria do binomial experiments meet?

1 answer:

3 0

Answer:

Each of the n tests must have two success p or failure q results, they are mutually exclusive. The probability of success p of an event is fixed or constant, likewise for the probability of failure q. The tests are independent.

Step-by-step explanation:

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Calculus question plzzzz

miss Akunina [59]

Answer:

Step-by-step explanation:

$f(x)=\frac{1}{\sqrt{x} }\\f'(x)=-\frac{1}{2} x^{-\frac{3}{2}}\\\\f'(4)=-\frac{1}{2} 4^{-\frac{3}{2} }=-\frac{1}{2} \frac{1}{4^\frac{3}{2} } \\=-\frac{1}{2} *\frac{1}{8}=-\frac{1}{16} \\when x=4\\y=f(x)=\frac{1}{\sqrt{4} } =\frac{1}{2} \\\\eq.~ of ~tangent ~line~is\\y=-\frac{1}{2} -\frac{1}{16} (x-4)$

3 0

3 years ago

Solve for y, then find the value of y when given x= -2

8090 [49]

Your answer will be c.

7 0

2 years ago

The predicted cost c (in hundreds of thousands of dollars) for a company to remove p% of a chemical from its waste water is show

alukav5142 [94]

We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))

This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))

The average value of this function over the interval [50, 55] is given by the integral
$\frac{1}{55-50} \times \frac{-124}{11} \int\limits^{55}_{50} {(\frac{1}{x+10}+\frac{10}{x-100})} \, dx$
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494

The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000