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Zina [86]
3 years ago
5

Determine whether or not the given procedure results in a binomial distribution. If not, identify which condition is not met. Su

rveying 2828 people to determine which statistics courses they have taken.
Mathematics
2 answers:
dlinn [17]3 years ago
7 0

Answer:

No, the given procedure doesn't result in a binomial distribution.

Step-by-step explanation:

We can identify if a given procedure results in binomial distribution by observing whether these four conditions are met or not.

Condition 1: Each observation should be independent, it must not depend on the result of previous observation.

Condition 2: The probability of success should stay same from trial to trial.

Condition 3: n is fixed (the number of observations)

Condition 4: There are only two outcomes success or failure.

Surveying 2828 people to determine which statistics courses they have taken.

Condition 3 is satisfied since n is fixed

Condition 1 is satisfied since each observation is independent

Condition 4 is not satisfied since there can be more than 2 answers from the people (statistics courses can be many).

IRINA_888 [86]3 years ago
3 0

Answer:

No, the given procedure doesn't result in binomial distribution.

Step-by-step explanation:

For any procedure to be a binomial distribution, these below four conditions should be met;

<u>Condition 1</u>: Each and every observation should be independent from the other observations.

<u>Condition 2</u>: The probability of success(p) should always be same for each trial.

<u>Condition 3</u>: Number of trials(n) must be fixed.

<u>Condition 4</u>: There must be only two outcomes success or failure.

Now, the procedure given to us is : Surveying 2828 people to determine which statistics courses they have taken.

In this procedure;

  • Condition 1 is satisfied since each observation is independent from other.
  • Condition 3 is satisfied as n is fixed for surveying 2828 people.
  • Condition 4 is not satisfied because there can be more than 2 answers from the people regarding which statistics courses they have taken as there as many statistics courses.

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Step-by-step explanation:

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Proof -

a.)

Hypothesis testing problem :

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H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}}  + \frac{s_{2}^{2} }{n_{2}} } }

Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42}  + \frac{0.02496 }{42} } }

Z = \frac{0.127 }{\sqrt{0.001468}}

Z = \frac{0.127 }{0.0377}

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As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

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