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guapka [62]
3 years ago
6

The temperature overnight in Sitka, Alaska was 12 below zero. How should this be written?

Mathematics
1 answer:
Bingel [31]3 years ago
6 0

Answer:

-12°

Step-by-step explanation:

it is negative because it it below zero.

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16) What is the percent of increase from 15 to 60?
Eduardwww [97]

Answer:

400%

Step-by-step explanation:

3 0
3 years ago
A firm producing 7 units of output has an average total cost of Rs. 150 and has to pay Rs.350 to its fixed factors of production
maria [59]

Rs 100 of the average total cost is made up of variable costs.

Step-by-step explanation:

Given:

Number of output the firm produces= 7 units

Average cost of the output= Rs. 150

fixed factors of production = Rs.350

To Find:

How much of the average total cost is made up of variable costs=?

Solution:

we know that,

Average total cost= total cost/ number of output units produced

substituting the values, we get

150=\frac{\text{Total cost}}{7}

Total cost= 1050

we know that Total fixed cost = 350

Total cost = Total fixed cost + Total variable cost

plug in the known values.

1050= 350 + Total variable cost

Total variable cost = 1050-350

Total variable cost =700

For 7th unit \frac{700}{7} = 100

5 0
4 years ago
Keith and Michelle went out to dinner. the total cost of their meal, including the tip, came to $53.70. if the combined tip came
insens350 [35]

If you subtract the $9.60 from the $53.70 you would be taking out the tip which would be $44.10. Then if you divide the $44.10 by 2, because they both payed equally, you would get $22.05 per person, not including the tip.

7 0
3 years ago
A number cube is rolled 14 times and the results are recorded in the table.
Arlecino [84]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
Keith_Richards [23]

Answer:

  32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

  C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

  ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

  ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

__

For t=20, this is ...

  ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

  (150 -C)/(60 -C) = 4.225

  1 +90/(60 -C) = 4.225

  C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

7 0
3 years ago
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